4x^2+28=32x

Solution for 4x^2+28=32x equation:

4x^2+28=32x

We move all terms to the left:

4x^2+28-(32x)=0

a = 4; b = -32; c = +28;
Δ = b2-4ac
Δ = -322-4·4·28
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-24}{2*4}=\frac{8}{8}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+24}{2*4}=\frac{56}{8}
=7
$